状态同步之平滑移动

状态同步的游戏在同步坐标时会因为网络延迟卡顿，怎么解决?

import * as cc from "cc";
import main_nodes from "./main_nodes";
import { _decorator, Component, Node } from "cc";
const { ccclass, property } = _decorator;

@ccclass("main")
export class main extends Component {
	@property(main_nodes)
	nodes = new main_nodes();
	/* ------------------------------- segmentation ------------------------------- */
	onLoad(): void {
		let delay_n = 0;

		this.node.on(
			cc.Node.EventType.TOUCH_START,
			(event: cc.EventTouch) => {
				this.unscheduleAllCallbacks();
				cc.Tween.stopAllByTarget(this.nodes.move_point);
				this._move_b = false;
			},
			this
		);

		this.node.on(
			cc.Node.EventType.TOUCH_MOVE,
			(event: cc.EventTouch) => {
				// 模拟延迟时间
				delay_n += Math.random() * 100;

				this.scheduleOnce(() => {
					this.on_server_move(event.getUILocation());
				}, delay_n * 0.001);
			},
			this
		);

		this.node.on(
			cc.Node.EventType.TOUCH_END,
			(event: cc.EventTouch) => {
				delay_n = 0;
			},
			this
		);
	}

	/** 移动状态 */
	private _move_b = false;
	/** 目标点 */
	private _target_position_v3: cc.Vec3;

	protected update(dt: number): void {
		if (!this._target_position_v3) {
			return;
		}

		this.nodes.move_point.worldPosition = this.nodes.move_point.worldPosition.clone().lerp(this._target_position_v3, dt * 10);

		if (this.nodes.move_point.worldPosition.clone().subtract(this._target_position_v3).lengthSqr() < 4) {
			this._move_b = false;
		}
	}

	on_server_move(position_v2_: cc.Vec2): void {
		this.nodes.real_move_point.worldPosition = cc.v3(position_v2_.x, position_v2_.y);

		// if (!this._move_b) {
		// 	this.scheduleOnce(() => {
		// 		this._target_position_v3 = cc.v3(position_v2_.x, position_v2_.y);
		// 	}, 0.1);
		// } else {
		// }
		this._target_position_v3 = cc.v3(position_v2_.x, position_v2_.y);

		this._move_b = true;
	}
}